# Problem
This function returns the number of times a number appears in the array.

```python
def count_occurrences(arr, num):
    count = 0
    for i in range(len(arr)):
        if arr[i] == num:
            count += 1
    return count
```
# Solution
The number of loops is determined by the size of the array $N$. The instructions inside the loop are constant-time. It follows that the time complexity is $O(N)$.

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